25x^2+50x+41=0

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Solution for 25x^2+50x+41=0 equation:


Simplifying
25x2 + 50x + 41 = 0

Reorder the terms:
41 + 50x + 25x2 = 0

Solving
41 + 50x + 25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
1.64 + 2x + x2 = 0

Move the constant term to the right:

Add '-1.64' to each side of the equation.
1.64 + 2x + -1.64 + x2 = 0 + -1.64

Reorder the terms:
1.64 + -1.64 + 2x + x2 = 0 + -1.64

Combine like terms: 1.64 + -1.64 = 0.00
0.00 + 2x + x2 = 0 + -1.64
2x + x2 = 0 + -1.64

Combine like terms: 0 + -1.64 = -1.64
2x + x2 = -1.64

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -1.64 + 1

Reorder the terms:
1 + 2x + x2 = -1.64 + 1

Combine like terms: -1.64 + 1 = -0.64
1 + 2x + x2 = -0.64

Factor a perfect square on the left side:
(x + 1)(x + 1) = -0.64

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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